There are 3 chocolate bars, 5 hard candies, and 2 lollipops in a candy jar.?

Question

If a person picks one out without looking what is the
possibility that the person would pick a hard candy??

Answer 1

1. Probability in this problem is is determined as follows: the number of hard candies/ all possibilities.

2. Therefore, you will divide the number of hard candies by the combined number of chocolate bars, lollipops, and hard candies.

3. This gives you (in numbers) 5/(5+3+2)

4. Simplified, this becomes: 5/10

5. In its simplest form this is 1/2; as a percent it is 50%.

Answer 2

3 chocolate bars + 5 hard candies + 2 lollipops
= 10 chances
5 hard candies out of 10 = 1 in 2 possibilities
(1/2 or 0.5 or 50%)

Answer 3

5/10 or 50% chance. Since there are 10 items in the jar and 5 of them are hard candies, her chances of picking up a hard candy are higher than the bars or lollipops since there are fewer of those.

Answer 4

ahem.. 1 out of 10 chance.... 5+2+3 = 10.... whew that was tough...

But then again, just because the person is not looking, doesn't mean they can't avoid the lollipop sticks and the chocolate bars by feeling around. :)

Answer 5

It's 50%. Think about it:

There are 10 candies altogether. 5 of them are hard candies, which is half. Hence, 50%...I think.

Answer 6

Its a 1 out of 9 chance.

Answer 7

5 out of 10. 50 percent chance.