English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

2007-03-08 13:57:23 · 8 answers · asked by anonymous 2 in Home & Garden Garden & Landscape

i have to make a park with it

2007-03-08 14:14:06 · update #1

8 answers

Make it about 75 feet in diameter.





bwg

2007-03-12 14:27:17 · answer #1 · answered by Bates Water Gardens 4 · 0 1

If you have paths in it, you can make it as big as you want. But if you have to do the weeding from outside, make it so you never have to reach more than 3 feet to get to the center. So, that would be a 6 foot diameter.

2007-03-08 19:24:30 · answer #2 · answered by Kacky 7 · 0 0

well u didnt' give us too much info for us to give u the answer..well u kno that a diameter is an edge of a circle to the opposite right? so if u can find the radius, just times it by 2.

or if u are given the area of the circle just divided the area by pi, find the square root of it, then multiply it by 2.

2007-03-08 14:09:37 · answer #3 · answered by MiMi 1 · 0 0

the quantity of fencing often is the size of the circumference of the circle. the place C is the circumference and d is the diameter: C = ?d Plug in d = 80 4 m: C = 84? m ? 263.89378 m

2016-10-17 22:19:09 · answer #4 · answered by ? 3 · 0 0

mmm good one , when ive built one of these , ive used 6ft and 8 ft , because you have to get in to weed them
really depend on your garden size if you have a large garden use both sizes ,use a peice of string put in a small stake , roughty where you need it and walk around , you cant go wroung

2007-03-08 14:04:42 · answer #5 · answered by Anonymous · 0 0

just measure across, that is the diameter

2007-03-08 14:01:16 · answer #6 · answered by jstrmbill 3 · 1 0

just measure from one side to the other passing through the presice center.

it is not radiusx3.14xsquared -- that's the area.

2007-03-08 14:04:07 · answer #7 · answered by ael2112 2 · 1 0

2 X 3.14 X radius .

2007-03-08 14:01:30 · answer #8 · answered by tony c 3 · 0 0

fedest.com, questions and answers