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Ex. lead will react with hydrochloric acid to produce lead(II) chloride and hydrogen. How many moles of hydrochloric acid are needed to completely react with 0.36 mol of lead?

HOW DO I SOLVE A PROBLEM LIKE THIS???

2007-03-08 13:57:17 · 4 answers · asked by Anonymous in Science & Mathematics Chemistry

4 answers

First you must have a balanced equation

Pb + 2HCl == PbCl2 + H2

Convert the 0.36 g of Pb to moles.

Miltiply that by the molar ration of 2 moles HCl / 1 mole Pb.

This gives you moles of HCL. You can convert that number to grams of HCl, if needed, my multiplying by the Mol. Mass

2007-03-08 14:04:49 · answer #1 · answered by reb1240 7 · 0 0

Wow, i'm doing the same thing.

1. Write out your equation
2. You have your moles of lead already, so make a mole to mole ration. find the coefficient of lead, and hydrochloric acid.
3. Multiply .36 times this ratio, and you'll have your answer.

I know it wasn't too helpful but these are the steps. It would take a while to find the answer.

2007-03-08 22:19:43 · answer #2 · answered by Donovan G 5 · 0 0

First you need to balance your chemical equation then you use the mole ratio to go from mols of lead to mols of HCl acid.

2007-03-08 22:06:13 · answer #3 · answered by Tennischica17 1 · 0 0

first u write an equation and balance and get the ratio of Pb to HCl..

Pb + HCl -------------> PbCl2 + H2

balancing equation gives

Pb + 2HCl ---------> PbCl2 + H2

2 mol of HCl needed for 1 mol of Pb
therefore 0.36 mol of Pb requires :- 2 X 0.36 mol of HCl = 0.72mol

2007-03-08 22:07:01 · answer #4 · answered by greeek 1 · 0 0

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