fector help?

0 ⤊

(x^3-27)

2007-03-08 13:56:45 · 2 answers · asked by ash d 2 in Science & Mathematics ➔ Mathematics

2 answers

This is a difference of cubes:

(x-3)(x^2+3x+9)

That is the complete factorization.

In general, a^3-b^3 = (a-b)(a^2+ab+b^2) and a^3+b^3 = (a+b)(a^2-ab+b^2)

In this case, a=x and b=3 (in the difference of cubes)

2007-03-08 13:59:51 · answer #1 · answered by Aegor R 4 · 0⤊ 0⤋

x^3-27
=(x)^3-(3)^3
=(x-3) {(x)^2+x*3+(3)^2} [a^3-b^3=(a-b)(a^2+ab+b^2]
=(x-3) (x^2+3x+9)

2007-03-08 22:29:51 · answer #2 · answered by alpha 7 · 0⤊ 0⤋