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4(y-3)+8y

2007-03-08 13:54:47 · 14 answers · asked by EUROxB@B3 1 in Education & Reference Homework Help

14 answers

yea the are right 12y-12

2007-03-08 13:58:10 · answer #1 · answered by Anonymous · 0 2

4(y-3)+8y
Step 1: Distribute the 4 to both the y and the 3.
So it becomes 4y-12+8y.

Step 2: Combine like terms. Since there are only y's that need combining, the final answer is 4y+8y-12= 12y-12=12(y-1)

Hope that helps!

2007-03-08 21:59:27 · answer #2 · answered by gmana792 1 · 0 2

1. Distribute: 4(y-3) = 4y - 12

2. Then add the 8y, so 4y - 12 +8y = 12y - 12

2007-03-08 22:02:56 · answer #3 · answered by Pythagoras 7 · 0 2

In order to simplify the equasion, you would first multiply out the 4(y-3), which would be 4y-12.
The equasion would then be : 4y-12+8y
The next step would be to add the y components meaning
4y-12+8y= 12y-12

12y-12 would be the simplification.

2007-03-08 22:00:55 · answer #4 · answered by Jon B 3 · 0 2

4(y-3)+8y
4y-12+8y (multiply 4 by each figure in the parenthesis)
12y -12 (add the common terms... 4y and 8y)

thats it if you are simplifying...i think.. .. or you might be able to divide the whole thing by one and have y-1.... lets see

12y-12
12=12y
y=1

1y-1
1y=1

yeah... you can simplify it all the way down to y-1.

2007-03-09 01:59:36 · answer #5 · answered by MnKLmT 4 · 0 1

distribute the 4 into the parentheses.
4y-12+8y
now combine like terms
12y-12

2007-03-08 21:57:56 · answer #6 · answered by Anonymous · 0 2

this is not at all a equation. 4(y-3)+8y equals what?????
the quesiton itself is wrong

2007-03-10 03:03:55 · answer #7 · answered by more1708_par 2 · 0 0

Just distribute the 4

Perenthasis are always 1st

2007-03-08 21:59:00 · answer #8 · answered by Anonymous · 0 2

4y-12+8y
12y-12

2007-03-08 22:00:15 · answer #9 · answered by dropkickchick 3 · 0 2

4y-12+8y
12y-12

2007-03-08 21:57:10 · answer #10 · answered by vospire s 5 · 0 2

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