yea the are right 12y-12
2007-03-08 13:58:10
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answer #1
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answered by Anonymous
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4(y-3)+8y
Step 1: Distribute the 4 to both the y and the 3.
So it becomes 4y-12+8y.
Step 2: Combine like terms. Since there are only y's that need combining, the final answer is 4y+8y-12= 12y-12=12(y-1)
Hope that helps!
2007-03-08 21:59:27
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answer #2
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answered by gmana792 1
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1. Distribute: 4(y-3) = 4y - 12
2. Then add the 8y, so 4y - 12 +8y = 12y - 12
2007-03-08 22:02:56
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answer #3
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answered by Pythagoras 7
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In order to simplify the equasion, you would first multiply out the 4(y-3), which would be 4y-12.
The equasion would then be : 4y-12+8y
The next step would be to add the y components meaning
4y-12+8y= 12y-12
12y-12 would be the simplification.
2007-03-08 22:00:55
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answer #4
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answered by Jon B 3
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4(y-3)+8y
4y-12+8y (multiply 4 by each figure in the parenthesis)
12y -12 (add the common terms... 4y and 8y)
thats it if you are simplifying...i think.. .. or you might be able to divide the whole thing by one and have y-1.... lets see
12y-12
12=12y
y=1
1y-1
1y=1
yeah... you can simplify it all the way down to y-1.
2007-03-09 01:59:36
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answer #5
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answered by MnKLmT 4
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distribute the 4 into the parentheses.
4y-12+8y
now combine like terms
12y-12
2007-03-08 21:57:56
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answer #6
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answered by Anonymous
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this is not at all a equation. 4(y-3)+8y equals what?????
the quesiton itself is wrong
2007-03-10 03:03:55
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answer #7
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answered by more1708_par 2
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Just distribute the 4
Perenthasis are always 1st
2007-03-08 21:59:00
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answer #8
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answered by Anonymous
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4y-12+8y
12y-12
2007-03-08 22:00:15
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answer #9
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answered by dropkickchick 3
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4y-12+8y
12y-12
2007-03-08 21:57:10
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answer #10
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answered by vospire s 5
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