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With a balanced equation where there is only "one" product, how many moles of oxygen2 are needed to produce 3.91 moles of Iron(111) oxide?

2007-03-08 13:46:44 · 2 answers · asked by honest abe 4 in Science & Mathematics Chemistry

You are correct, you will get the 10 points since you were also the first to answer

2007-03-08 14:12:27 · update #1

I have another question if you would like to take a crack at it, there's 10 points in it for you.

2007-03-08 14:15:15 · update #2

2 answers

OK, with iron, there are two ionic forms, ferrIC and ferrOUS. As you have noted, the "IC" has a +3 charge.
So 4 Fe + 3O2 -> 2Fe2O3

Now the ratio of oxygen to ferric oxide by moles is 3 to 2. Then by proportion 3/2 = x/3.91or
11.73 = 2x and x = 5.86 moles O2. TA DA

2007-03-08 13:52:58 · answer #1 · answered by cattbarf 7 · 1 0

a million) H2(g) + Cl(g) --> 2HCl (aq) 2) SO2(g) + H2O(l) --> H2SO3 3) 4Fe(s) + 6O(g) --> 2Fe2O3 (s) 4) H2O2 (aq) --> H2(g) + O2(g) whilst doing those you purely could desire to be responsive to what the oxidation states of the atoms are. then you definately can write the chemical reaction and stability it employing stoichiometry. the biggest to balancing equations is to ensure you would be able to desire to comparable quantity of each and every species on the two facets. Its least complicated to chop up them out and count huge form them in my opinion. synthesis reactions a million) HCl (aq) + Al(s) --> AlCl3 (s) + H2(g) 2) H2O (l) + Na(s) --> NaOH (aq) + H2(g) 3) 2Mg(s) + Pt(OH)4 --> 2Mg(OH)2 + Pt(4+) With those, you're doing what's called a single displacement reaction. you purely transpose the metals. If hydrogen is being replaced, in many situations it is going to form hydrogen gas. make specific you envision the periodic table to ensure if the steel you're changing with is greater reactive then the only that it could be changing. the better and the greater left the element, the greater reactive with non-metals it is going to likely be. decomposition O2 --> 2O(2+) PCl5 --> P(5+) + 5Cl(-) For the states, any steel by using itself that doesnt have a can charge on it is going to likely be interior the forged state. in many situations ionic species and metals with a can charge (like Pt(4+) would be interior the aqueous state (aq). Water would be liquid (l), and hydrogen would be gas (g). Neutralization a million) HCl(aq) + LiOH (aq) --> LiCl(aq) + H2O(l) 2) 2H2SO4 (aq) + 4NaOH (aq) --> 2Na2SO4 (aq) + 4H2O (l) 3) BaCl2 (aq) + Na2CrO4 (a) --> BaCrO4 (aq) + 2NaCl (aq) nuetralization reactions are an identical different than its greater like a double alternative reaction. Acids and bases like the 1st one will continuously form a salt and water. Double displacement reactions a million) 2FeCl3 (aq) + 3Na2SO4(aq) --> 6NaCl (aq) + Fe2(SO4)3 (aq) purely turn the two metals and stability. pay interest to oxidation states on the species. you're welcome for doing all your hw. you greater effective supply me terrific answer ;)

2016-10-17 22:17:55 · answer #2 · answered by ? 3 · 0 0

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