2007-03-08 13:37:02 · 7 answers · asked by Lizzie 5 in Science & Mathematics ➔ Physics
Planer with the two hydrogens at about a 105 degree angle with the oxygen in the center.
2007-03-08 13:39:41 · answer #1 · answered by Flyboy 6 · 1⤊ 0⤋
acc to VSEPR concept, geometry of a molecule is predicated upon the completed no. of e-pairs (bondin & non-bondin) around the considered necessary atom and shape of the molecule is predicated upon the orientation of the e-pairs interior the gap around the considered necessary atom. a molecule havin in basic terms bond pairs (bp) around the considered necessary atom will hav usual shape or geometry yet those havin bond AND lone pairs (lp) will hav distortd shape. whether considered necessary atom is surrounded via bonded e-pairs with numerous atoms, the fee of repulsion is purely no longer the comparable and as a result shape of molecules would be extraordinary, case in point CHCl3. bp-bp repulsions boost bond perspective yet lp-lp replsions convey the bond closer and could cut back bond perspective, eg: CH4 (no lp) has perspective > NH3 (a million lp) > H2O (2 lp)
2016-12-18 18:24:40 · answer #2 · answered by ? 3 · 0⤊ 0⤋
like a V.
You start off with a hydrogen molecule on each side like so:
H-O-H
But then oxygen has two unpaired electrons sitting at the "top" and that bends it into a slightly v shape as the electrons exert pressure on the covalent bonds.
"
O
/ \
H H
2007-03-08 13:43:49 · answer #3 · answered by Anonymous · 1⤊ 0⤋
See link below
2007-03-08 14:08:28 · answer #4 · answered by Johnny 5 · 0⤊ 0⤋
Triangular or pyramidal depending on if you consider three dimensional.
2007-03-08 13:40:55 · answer #5 · answered by Sophist 7 · 0⤊ 0⤋
It has a tetrahedral bent geometry.
2007-03-08 13:42:42 · answer #6 · answered by bdizzle329 1 · 0⤊ 1⤋
O
/ \
H H
2007-03-08 13:42:35 · answer #7 · answered by aliterit 2 · 0⤊ 0⤋