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A study on blood types in a population found the following genotypic distribution among the people sampled: 1101 were MM, 1496 were MN and 503 were NN. Calculate the allele frequencies of M and N.what are the 3 phenotype frequencies as a percent?

please show how you got the answer

2007-03-08 13:21:49 · 2 answers · asked by mundoskisis4life 1 in Education & Reference Trivia

2 answers

Been a while since I had an evolution course, but I think I can help.

First, you need to know the number of people sampled:

1101 + 1496 + 503 = 3100

The % for the phenotypes in the populations would be
MM = 1101/3100 = 0.36 or 36%
MN = 1496/3100 = 0.48 or 48%
NN = 503/3100 = 0.16 or 16%
IF the sample is representative of the population.


To calculate the allele frequencies:

everyone with MM has two Ms
everyone with MN has one M
.36 + 1/2(.48) = .60 or 60% M

N, therefore is .40, or 40%


see link in sources box if you need more help with problems like these

2007-03-08 15:01:30 · answer #1 · answered by copperhead 7 · 0 0

in case you have the frequency of the recessive phenotype (as an occasion, the type of folk who won't be able to place their tongue divided by skill of the great type of folk you're finding at), you have the frequency of homozygous recessive genotype: q^2. Then, you could take the sq. root of that to get q, that's the allele frequency of the recessive gene. The equation for allele frequencies is p + q = a million, so which you will then rearrange the equation and use what you calculated for q to get p: p = a million - q. Now you have p and q. p^2 is the frequency of homozygous dominant genotypes. 2pq is is the frequency of the heterozygotes, and as I stated till now, q^2 is the frequency of the homozygous recessive genotype.

2016-11-23 16:23:35 · answer #2 · answered by ? 4 · 0 0

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