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Mr. Lim had a large wooden cube that measured 4 inches on each edge. He wanted to cut it into 64 smaller cubes that measured 1 inch on each edge. If rearranged the pieces before each cut, what is the least number of cuts he would have to make?

2007-03-08 13:15:59 · 5 answers · asked by pimp 1 in Science & Mathematics Mathematics

5 answers

Fist of all, inorder to cut it into 64 pieces it would be 4 rows of 4 and 4 rows high.

Like a rubicks cube but with 4 rows instead of 3

The logical way would be to cut 3 rows Horizontally then 3 rows Vertically then 3 rows acrooss the top. This would give you 64 even cubes.

Dude, this is a good one!

I will have to say the least number of cuts is 9.

It is the only logical way.

2007-03-08 13:37:58 · answer #1 · answered by D - VOK 2 · 0 0

The answer is 4.

1. He cuts the pieces vertically in half.
2. He stacks them on top of each other, vertically.
3. He cuts the whole tower in half with one vertical cut.
[2 cuts so far]
4. He rearranges the pieces back into a cube.
5. He cuts them in half horizontally.
6. He puts the four top pieces behind the bottom four, and makes another horizontal cut, cutting everything in half.
You now have 64 pieces :)

2007-03-08 21:26:31 · answer #2 · answered by pedros2008 3 · 0 0

I think 6. I'm not sure but if you just cut 3 slits going one way and then 3 cuts going perpendicular to the first 3 then you have 64 cubes.

2007-03-08 21:22:05 · answer #3 · answered by Katie 2 · 0 0

60

2007-03-08 21:25:47 · answer #4 · answered by Anonymous · 0 0

6. Put them in a line each time and just cut them in half....Rotating every once in a while to make sure they remain squares.

2007-03-08 21:25:01 · answer #5 · answered by apple_dax 2 · 0 0

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