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The region bounded by y=2/(1+x^2), y=0, x=0 and x=8 is rotated about the line .
Using cylindrical shells, set up an integral for the volume of the resulting solid.

I know that the limits are 0-8
using the basic cylindar formula i got the integral
2pi((2x)/(1+x^2)) but its wrong

2007-03-08 13:12:23 · 1 answers · asked by ♡♥EM♡♥ 4 in Science & Mathematics Mathematics

1 answers

you should set up like this
intergral from 0 to8 of 2pi(8-x)(2/(1+x^2)) dx
i let you do the rest
answer round 37.937pi
good luck

2007-03-08 13:25:36 · answer #1 · answered by Helper 6 · 0 0

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