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If 10.00 grams of KCl are dissolved in water to make a solution of 0.153 L, the density is found to be 1.048 g/cm3. Calculate the molality of the solute.

2007-03-08 13:07:46 · 2 answers · asked by Anonymous in Science & Mathematics Chemistry

2 answers

Molality is moles solute over kg solvent.

Find the moles KCl. That's the easy part.

Next, you need to identify your solvent. It's water. You can figure out how many kg of water you have by using conversion factors:

L water ---> g water (using density) ---> kg water

Once you've got those two quantities, just plug them into your molality equation and you're done. Remember the little "m" to represent molality.

2007-03-08 13:18:51 · answer #1 · answered by Mystery Viscera 2 · 0 0

I guess you can use my question as a ref.

If 12.20 grams of LiCl are dissolved in water to make a solution of 0.103 L, the density is found to be 1.087 g/cm3. Calculate the molality of the solute.

Correct, computer gets: 2.87803727294173
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This is how I solved this:

12.9*.103=118.553 / MM of LiCl=42.39 =2794210944

2007-03-08 14:17:03 · answer #2 · answered by Raki 3 · 0 0

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