If you can figure this out your much smarter then me?

Question

A ladder is 25 ft long. THe ladder needs to reach to a widow that is 24ft abocve the ground. HOw far away from the building should the bottom of the ladder be placed. O by the way this is a math problem

Answer 1

In order to do that you'll have to use the pythagorean theorm.

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left side is a, bottom is b, diagonal is c
a^2 + b^2 = c^2
a = 24, b = ?, c = 25

so plug in the numbers and solve.

By the way, never try to use a 25 ft ladder on a 24 ft height. The bottom will be so close to the wall that it will be unstable and you will fall back and break your neck.

Answer 2

the ladder will be the hypotenuse of a right triangle. the distance from the window to the ground is 1 of the legs so

25^2-24^2=x^2
625-576=x^2
x^2=49
x=7


the bottom of the ladder should be 7' from the wall.

Answer 3

Pythagorean theorem

The ladder is the hypotenuse, so
a^2 + 24^2 = 25^2
a^2 = 625 - 576
a^2 = 49
a = 7

Answer 4

Think of it as a big right triangle. The height is 24...the hypoteneuse is 25.

A^2 + B^2 = C^2

24^2 + B^2 = 25^2

576 + B^2 = 625

B^2 = 49

B = 7

Answer 5

STEP BY STEP GUIDE!
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it helps
use the Pythagorean theorem
a^2+b^2=c^2
a and b stand for sides of the triangle
c stands for the hypotenuse
you are given one leg of the triangle right triangle (24ft)
the hypotenuse is 25ft
plug them in!
24^2+b^2=25^2
square the two numbers
24^2=576
25^2=625
576+b^2=625
subtract both sides by 576
b^2=49
take the square roots of both sides
b=7
7ft is your answer

Answer 6

I believe it is
a^2+b^2=c^2
so 25 is c= 25^2=625
then 24^2=576

625-576=49 square root of 49 is 7. So 7ft.

Answer 7

it is simple application of Pythagoras's Theorem
hypotenuse is 25
one side is 24
the other one is x

x^2 + 24^2 = 25^2

Solve for x...

x^2 = 25^2 - 24^2 = 49

x = 7 feet

Answer 8

1 feet apart