in any trinagle the length of 2 sides must be larger than the length of the 3rd side. in any trinagle the difference (larger minus smaller) of any 2 sides must be less than the 3rd side. the lengths of 2 sides of a triangle are 5 and 14 and the third side is a whole number.whats the difference between the largest possible length and the smallest possible length for the 3rd side.
2007-03-08 12:27:19 · 3 answers · asked by huhwhatcaca 2 in Science & Mathematics ➔ Mathematics
13
With triangles it is a^2 + b^2= C^2
So since 14 is the largest lets make that 14. 14^2=196
196- 5^2(25)=171
THE SQUARE ROOT OF 171 IS 13.07 for the smallest.
196+25=221 and square root of 221=14.866 for the largest the third side can be.
2007-03-08 13:08:22 · answer #1 · answered by RoxieC 5 · 0⤊ 0⤋
The largest the third side can be is 14 + 5 = 19
The smallest the third side can be is 14 - 5 = 9
19 - 9 = 10
2007-03-08 20:43:42 · answer #2 · answered by theoryofgame 7 · 0⤊ 0⤋
The right answer is 8
Largest possible length = x say
Smallest = y.
x < 14+5 => x = 18 [ x cannot be 19, it is a strictly-lesser-than inequality]
y > 14 - 5 => y = 10 [y cannot be 9 for the same reasons as before]
=> the difference is x-y = 8
2007-03-09 01:35:24 · answer #3 · answered by FedUp 3 · 0⤊ 0⤋