If 13.30 grams of KCl are dissolved in water to make a solution of 0.154 L, the density is found to be 1.064 g

Question

If 13.30 grams of KCl are dissolved in water to make a solution of 0.154 L, the density is found to be 1.064 g/cm3. Calculate the molality of the solute.

Answer 1

I guess you can use my question as a ref.

If 12.20 grams of LiCl are dissolved in water to make a solution of 0.103 L, the density is found to be 1.087 g/cm3. Calculate the molality of the solute.

Correct, computer gets: 2.87803727294173
Top

This is how I solved this:

12.9*.103=118.553 / MM of LiCl=42.39 =2794210944

Answer 2

MM KCl=seventy 4.4 g/mol 11.10 g/seventy 4.4 g/mol=0.149 mole KCl From the density all of us be attentive to that a million mL weights a million.053 g so 153 mL weight 161.a million g: that's the finished weight of the answer Weight of H2O=161.a million - 11.a million=a hundred and fifty g = 0.15 Kg molality=0.149/0.15 = 0.a million m the different answer isn't good by way of fact molality is defined as moles/kg solvent and not answer