Bubba rushed 67 yards in one football game and 75 yards in anothre. Which equation can be used to find n, the number of yards Bubba needs in the next game in order to have an average of 70 yards rushing per game?
2007-03-08 12:15:15 · 5 answers · asked by Julie J 1 in Science & Mathematics ➔ Mathematics
(67 + 75 + n)/3 = 70
2007-03-08 12:18:17 · answer #1 · answered by ecolink 7 · 0⤊ 0⤋
Average is the sum total divided the number of times.
1) (67+75+n)/3
you know the yards in the first and second football game. The third is unknown and hence n. And it is 3 games so to get an average you divide by 3.
2) (67+75+n)/3 = 70
you know the average; so set up the equation as shown above.
3) (142+n)/3 = 70
4) 142+n = 210
Multiply both sides by 3
5) n = 210-142
Substract 142 from both the sides
6) n = 68.
Bubba needs 68 yards in his 3 game to have an average of 70.
Double check your answer by adding: (67+75+68)/3 = 70
Hope this helped. :)
2007-03-08 20:34:41 · answer #2 · answered by india08_30 2 · 0⤊ 0⤋
(67 + 75 + N)/3 = 70
Explanation:
1. in order to find the average, you need to add all the numbers together then divide the sum by the number of numbers there are. Ex. 1 + 2 + 3 the average equals 2 because 1 + 2 + 3 = 6 and since there are 3 numbers 6/3 = 2
2. just apply that to this problem, except you don't know the number of yards for the next game, so that's "n"
2007-03-08 20:21:50 · answer #3 · answered by Caitlyn 3 · 0⤊ 0⤋
(65+75+n)/3=70
multiply each side by 3
65+75+n =210
140+n =210
subract 140 from each side
n= 70
2007-03-08 20:26:29 · answer #4 · answered by Natasha D 2 · 0⤊ 0⤋
67+75+n=3(average)
67+75+n=3(70)
67+75+n=210
n=68
2007-03-08 20:23:33 · answer #5 · answered by rollingballs92 2 · 0⤊ 0⤋