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Please help me integrate: cos x^1/2 dx

2007-03-08 12:00:50 · 1 answers · asked by Dexter D 1 in Science & Mathematics Mathematics

1 answers

If you put sqrtx=z 1/2sqrtx dx =dz and dx = 2z dz

So we have the Integral 2 Int zcos z dz.
By parts = 2 [ z sinz -Int sinz dz] =2 (z sin z +cos z)

= 2[(sqrt(x)*sin(sqrt x) +cos(sqrt x)]

2007-03-08 12:15:05 · answer #1 · answered by santmann2002 7 · 0 0

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