solve the inequalities
2007-03-08 11:35:43 · 10 answers · asked by bop 1 in Science & Mathematics ➔ Mathematics
take 8
now take x-5<21.
add 5 to both sides again. x-5+5<21+5. (-5 and 5 cancel)
x<26
now put it back together....
13
2007-03-08 11:39:47 · answer #1 · answered by silentzoom 1 · 0⤊ 0⤋
If you can solve equations, then this is rather simple
start by using the addition property
8+5 < x < 21 + 5 or 13 < x < 21 and it is solved
should you have to use the multiplication property of equality remember that when multiplying by a negative number the INEQUALITY sign changes..
Use this for all inequalities
2007-03-08 19:44:03 · answer #2 · answered by ? 3 · 0⤊ 0⤋
You've two inequalities:
8 < x - 5
and
x - 5 < 21
You can add five to both sides of an inequality and it will still be true. So:
13 < x and x < 26
This means that x is between 13 and 26, excluding the two values themselves.
2007-03-08 19:39:30 · answer #3 · answered by Gnomon 6 · 0⤊ 0⤋
13 < x < 26
2007-03-08 19:38:24 · answer #4 · answered by djs2012 2 · 1⤊ 0⤋
13
2007-03-08 19:40:34
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answer #5
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answered by JAMES 4
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13
2007-03-08 19:37:53
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answer #6
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answered by I Know Nothing 6
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8
2007-03-08 19:39:26
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answer #7
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answered by perplebunny 2
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8+5
13
add 5 for everything
2007-03-08 19:40:36
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answer #8
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answered by 7
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13
8 is smaller than x-5
x-5 is smaller than 21
x can be anything between 14 and 25
2007-03-08 19:40:27 · answer #9 · answered by jcurrieii 7 · 0⤊ 1⤋
to isolate the x - you need to do the opposite of what's happening to it - in this case 5 is being subtracted, so you need to add five to all three parts
2007-03-08 19:41:29 · answer #10 · answered by Zuri 3 · 0⤊ 0⤋