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Joe has 100 sports cards football, baseball, and basketball
he has 3x as many football as basketball and 10 x as many basketball as baseball how many of each card does he have?

2007-03-08 11:20:34 · 6 answers · asked by poohbear_huny 2 in Science & Mathematics Mathematics

6 answers

Say F = # football cards, K = # basketball, B = # baseball.

then F + K + B = 100
and F = 3 * K
and K = 10 * B

Then you see F = 3 * (10 * B) = 30 * B

Now put those into the first line:
30 B + 10 B + B = 100
41 B = 100
B = 2.439....
Well, you can only have integer numbers of cards, so it looks like the problem can't be exactly solved according to the problem statement.

Rounding off just a bit, you would get:
B = 2.439, K = 24.39, F = 73.17. (These add up to 99.999.) If we round them all to integers, they will add up to 99. But if you take B = 2, K = 24 and F = 74, you come pretty close to the problem statement.

This is pretty complicated for 4th grade math. Are you sure you stated the problem correctly? (The numbers would work out exactly if he had 123 cards: B = 3, K = 30, F = 90.)

2007-03-08 11:47:10 · answer #1 · answered by AnswerMan 4 · 0 0

first make an equation
F = football
B = basketball
b = baseball
F + B + b = 100

3x F = B
10x B = b
because B is in both I would suggest solving for B
F = 1/3 B
b = 1/10 B

put back into the orginal equation
1/3 B + B + 1/10 B = 100
common denominator - don't know if you need to do this step as the eqn above this in a calculator will give the same answer but anywho..

10/30 B + 30/30 B + 3/30 B = 43/30 B = 100
B = 69.8 = rounding up to 70

B = 70
b = 1/10 B = 1/10 x 70 = 7
F + 70 + 7 = 100
F = 23

or 3 x F = B, 3 x F = 70, F = 23.33333, round down to 23

F + B + b = 100
23 + 70 + 7 = 100

hope this helps

2007-03-08 19:45:21 · answer #2 · answered by biometallica 2 · 0 0

He is a fourth grader.the following process should be right for him.
First of all just think which type of card is the minimum.You can easily do it mentally and say that the baseball cards are the minimum
Let us assume that the no. of baseball card is 1
Then,no. of basketball cards will be10
And the no. of football cards are10X3=30
Now add them up
The total no. of cards are1+10+30
=41
Now if you divide actual total no. of cards by 41
you get the no. of baseball cards.
But I find that 100 is not exactly divisible by 41 Hence there is some mistake in the question or your typing
Please check up and correct the question
Add- The total no of cards should be a multiple of 41,say 41,
82,123,164.....
you divide the total no. by 41 to get the exact no of baseball cards.multiply the no of baseball cards by 10 to get the no. of basketball card and finally multiply the no. of basketball cards by 3 to get the number of football cards.

2007-03-08 20:12:18 · answer #3 · answered by alpha 7 · 0 0

This is no 4th grade problem, or, at least, shouldn't be. Using a pre-algebra approach,
. 1 baseball
10 basketball
30 football
41 total
There is no integer solution. You can't divide 100 by 41.
2 + 20 + 60 = 82
3 + 30 + 90 = 123

2007-03-08 19:56:32 · answer #4 · answered by Helmut 7 · 0 0

f=football b=basketball a=baseball

3f=b
10b=a
if a=2 then b=20 f=60 total=82
if a=3 then b=30 f=90 total=123

about:
3 baseball
24 basketball
73 football

2007-03-08 19:32:00 · answer #5 · answered by perplebunny 2 · 0 0

its been a while for me too. I would suggest going on a few websites to help you help him/her. Look around in his/her book. There has to be an explanation somewhere in the book for this type of problem.

2007-03-08 19:31:48 · answer #6 · answered by bamagurl722 2 · 0 0

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