How do I determine whether these lines are perpendicular or not?

Question

I don't know how to figure out of these 2 lines are perpendicular or not.

y=3x-8, y=-1/3x + 2

Please tell me if they are and not and tell me how you did it in an easy to understand way.

Answer 1

If the slopes of two lines have a product of -1, then the lines are perpendicular. The constant (b in y=mx+b) does not affect perpendicularity at all. The slope of the line y=mx+b is m, so the slopes are 3 and -1/3.

3 * (-1/3) = -3/3 = -1, so YES, the lines are perpendicular.

Answer 2

To determine if two lines are perpendicular, multiply their slopes; if you get an answer of (-1), then they are perpendicular.

In the first case, slope is 3.
In the second case, slope = (1/3)

3 times (-1/3) = -1.
Therefore, the lines are perpendicular.

Answer 3

y=3x-8, y=-1/3x + 2

first determine what the slope of each line is

3 , -1/3

if these two lines are perpendicular, then the slopes would be negative reciprocals of each other.....

WHICH THEY ARE!!!!!!!! cuz 3 made a negative reciprocal would be -1/3

and -1/3 made a negative reciprocal would 3

thus, they are perpendicular!!!!

Answer 4

perpendicular because the slopes(number in front of x) are negative reciprocals (flip the fraction, change sign)
3 and -1/3

Answer 5

Yes, they are perpendicular.
You see if the slopes (3 and -1/3), and check if they are negative reciprocals, which is if one's positive and the other is negative (3:positive, -1/3:negative) AND one is the other number's numerator and denominator are switched (3/1 flipped is 1/3).

Answer 6

they are

the slope of one is 3 and the slope of the other is -1/3
-1/3 is the negative inverse of 3

Answer 7

Slopes are neg. reciprocals, so the lines are perpendicular.