If anyone is good with chemistry problems, Please help~!?

Question

Disulfur dichloride, S2Cl2, can be made by treating molten sulfur with chlorine gas, according to the following unbalanced equation:
S8(l) + Cl2(g) ® S2Cl2(g)
How much S2Cl2 (in grams) can be produced if you start with 38.10 grams of sulfur, and 84.87 grams of chlorine gas?

Answer 1

Alls you have to do is find the limiting reactant using mole conversions. Then begin with the mass of the limited reactant and use molar conversion with the mol of S2Cl2 on top and the mol of the limited reactant. Make sure your original equation is balanced. Other than that...Im not gonna do it out for you, thats cheating :) But it should all be in your notes from your chem class

Answer 2

1.- First the chemical reaction:

S8 +4Cl2 --------> 4S2Cl2

according to this balanced equation you need 1 mol of sulphur plus 4 moles of chlorine to yield 4 moles of S2Cl2

2.- If you start with 38.10 grams of Sulfur and 84.87g of Chlorine we need to know how many moles they are equivalent to:

M(S8) = 256.52 g/mol
M(Cl2) = 71 g/mol

n(S8) = 38.10 g / 256.52 g/mol = 0.148 moles
n(Cl2) = 84.87 g / 71 g/mol = 1.195 moles

Ratio n(Cl2) / n(S8) = 1.195 / 0.148 = 8 it means 8 moles of chlorine for each mol of sulphur

Hence, limiting reactant is sulphur. It means that all the sulphur will be consumed.

3) We just need to know how many moles of S2Cl2 are produced by 0.148 moles of sulphur:

1 mol S8 --------- 4 moles S2Cl2
0.148 mol S8 ----- x

x = 0.592 moles of S2Cl2

M(S2Cl2) = 135 g/mol

Hence the mass of S2Cl2 = (0.592)(135) = 79.92 grams

4) You will get 79.92 grams of S2Cl2

Hope it helps!

Good luck!