please help me
2007-03-08 10:18:13 · 9 answers · asked by Drew C 1 in Science & Mathematics ➔ Mathematics
Combine like terms
12x^2 - 7x
2007-03-08 10:20:48 · answer #1 · answered by MsMath 7 · 1⤊ 1⤋
a million. 3^2+3+7=19 2. 3(4^2)+ 2(4)+2=fifty 8 3. 9(7^2) – 7 + 14 = 448 4. -3(a million^2) + 3(a million) + 10= 10 5. -(-2^2) + 2(-2) – 4= -12 6. 2(-4^2) + 6(-4) + 30 = 38 7. 6(-10^2) – 2(-10) + 7 =627 8. -4(-3^2) – 9(-3) – 8= -17 9. (-2^2) – 2(-2) + 4= 12 10. -5(-a million^2) – 3(-a million) + 4 =2 11. 12x2 + 4x – 3x2 + 8 + 10x + 3 = 9x2+14x+11 12. x2 + x + 3 – 4x – 4x2 – 10 by using combining like words. -3x2-3x-7 13. -x2 + 2x + 13 + 8 + 7x – 10x2= -11x2+9x+21 14. -3x2 – 4x + 10 – 4x2 – 10x – 3 – 8 – 3x – 4x2 = -11x2-17x-a million 15. 2x2 + 3x – 4x2 – x – 18 + 4x – 9x2 + 6x – 30 = 11x2+12x-40 8 sixteen. 50 17. -7 18. 19 19. -931 20. -383
2016-10-17 21:56:15 · answer #2 · answered by Anonymous · 0⤊ 0⤋
6x^2+3x-7+6x^2-10x+7
rearrange it:
6x^2 + 6x^2 + 3x - 10x - 7 + 7
now combine like terms:
(6x^2 + 6x^2) + (3x - 10x) - 7 + 7
12x^2 - 7x + 0
12x^2 - 7x
2007-03-08 10:22:11 · answer #3 · answered by Mathematica 7 · 1⤊ 0⤋
combine like terms
6x^2 + 6x^2 + 3x -10x + 7 - 7
12x^2 - 7x
2007-03-08 10:24:36 · answer #4 · answered by 7 · 1⤊ 0⤋
6x^2+3x-7+6x^2-10x+7
combine like terms...
12x^2-7x=0
find the common factor which in this case is x,
x(12x-7)=0
equate the two factors to zero
x = 0 and
(12x - 7) = 0
12x = 7
x = 7/12
2007-03-09 19:19:56 · answer #5 · answered by reddish 3 · 1⤊ 1⤋
combine the ones with the same exponents.
6X^2+6X^2
3X-10X
-7+7
12X^2-7X
2007-03-08 10:21:49 · answer #6 · answered by Finoai 2 · 2⤊ 0⤋
if you're simplifying, combine like terms to get: 12x^2-7x
If you're solving for x, then i'm assuming that expression equals 0.
so you can factor and get this:
x(12x-7) = 0
x = 0, 7/12
2007-03-08 10:21:17 · answer #7 · answered by David 3 · 1⤊ 0⤋
12x^2 - 7x
2007-03-08 10:21:32 · answer #8 · answered by The Tridentine Avenger 3 · 1⤊ 0⤋
12x^2 - 7x
x(12x-7)
2007-03-08 10:22:36 · answer #9 · answered by John S 6 · 1⤊ 0⤋