use distribution proberty, which you take:
6x* (3x-8) + 7*(3x-8)
18x^2 - 48x + 21x - 56
comebine like term
18x^2 -27x - 56
hope this helps
2007-03-08 10:11:05
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answer #1
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answered by 7
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Use the first, outside, inside last rule and figure it out.
First (6x*3x) = 18 x
outside (6x* -8) = -46x
inside (7*3x) = 21x
last (7* -8) = -56
so now you have -7x = -56
solve for x
x = -56/ -7 (should be 8)
Pretty easy, huh!
2007-03-08 18:14:14
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answer #2
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answered by Curly 4
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18x^2 - 27x - 56
You have to FOIL (multiply First terms, then Outer terms, then Inner terms, and lastly the Last terms) the two binomials.
So its: 6x * 3x = +18x^2
6x * -8 = -48x
7 * 3x = +21x
7 *-8 = -56
2007-03-08 18:12:36
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answer #3
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answered by YankeeKM91 2
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You have to multiply each part of the first bracket with the each part of the second.
For example, (a+b)(c-d) = ac-ad+bc-bd
(6x+7)(3x-8)
18x^2-48x+21x-56
simplified, the answer is 18x^2-27x-56
*"^2" = "squared"
2007-03-08 18:13:07
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answer #4
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answered by Deconstitutionalization 4
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An exponentially increasing number for moderately increasing values of 'x'!
OK, seriously -- those that have posted
"18x^2 - 27x - 56"
are correct.
This was a fun question. It brought back information from over 40 years ago! Cool!
2007-03-08 18:19:03
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answer #5
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answered by Rick C 1
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(6x*3x)+(6x*-8)+(7*3x)+(7*-8)
18x^2 - 48x + 21x - 56
18x^2 - 27x - 56
2007-03-08 18:12:52
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answer #6
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answered by babydoll32 2
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you just have to multiply each number by both numbers in the opposite set of parentheses.
you should get:
18x^2 + 21x - 32x - 56
which simplifies to:
18x^2 - 11x - 56
2007-03-08 18:12:39
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answer #7
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answered by Marie 2
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I got 18x squared-27x-56
2007-03-08 18:12:45
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answer #8
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answered by sarah 2
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18x squared -27x -56
x square is the x with a little 2 over it
2007-03-08 18:13:38
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answer #9
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answered by Anonymous
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(6x+7)(3x-8)
18x^2-32x+21x-56
18x^2-11x-56
2007-03-08 18:13:46
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answer #10
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answered by perplebunny 2
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