She hasn't felt any heat since she has been on the political scene. Why should she feel it, now?
Richardson is the man! The single most qualified candidate of any dem or rep.
.
2007-03-08 09:45:48
·
answer #1
·
answered by tlbs101 7
·
1⤊
3⤋
Obama had better watch his back. The mud has already started flying from the Reverend Hillary Clinton's camp. And if he gets too close for comfort, he might end up like one of these poor chaps.
http://members.tripod.com/~rcjustice/pres.html
2007-03-08 17:49:19
·
answer #2
·
answered by Anonymous
·
2⤊
0⤋
With all due respect, I'm not even looking yet. Give it another year, by then both parties will be done eating their young and some real consideration can be given to individual candidates.
2007-03-08 17:59:18
·
answer #3
·
answered by gimpalomg 7
·
1⤊
0⤋
Hillary Clinton won't feel the heat until she comes face to face with Rudy Giuliani and he lights a torch in her couchie.
2007-03-08 17:50:29
·
answer #4
·
answered by Anonymous
·
1⤊
1⤋
She sure as hell better not be feeling it from Osama-bama. Why in the hell would we elect someone with a name like that? I mean really folks. That's one crazy coincedence.
2007-03-08 17:49:43
·
answer #5
·
answered by Anonymous
·
2⤊
1⤋
I'm hoping this Obama fellow is genuine, because ''Her Thighness'' Hillary and her husband already turned my stomach with their lies and deception years ago.
2007-03-08 17:48:22
·
answer #6
·
answered by Anonymous
·
3⤊
1⤋
Probably. She'll have to lower the boom soon.
2007-03-08 18:20:32
·
answer #7
·
answered by Truth B. Told ITS THE ECONOMY STUPID 6
·
0⤊
0⤋
She's not upset or worried. I think she is a veteran, experienced, talented campaigner... a trooper. I even think she enjoys it.
2007-03-08 17:48:48
·
answer #8
·
answered by Lantern 3
·
1⤊
2⤋
It seems to me that Hillary is the only one worthy of being called professional in this campaign.
2007-03-08 17:45:00
·
answer #9
·
answered by Thought 3
·
1⤊
5⤋
she shouldnt because id give my vote to her or obama
2007-03-08 17:58:12
·
answer #10
·
answered by Anonymous
·
1⤊
1⤋