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the length of each leg of an isosceles triangle is 3 times the base. The perimeter of the triangle is 28 m. Find each side length

2007-03-08 09:41:56 · 7 answers · asked by Anonymous in Science & Mathematics Mathematics

7 answers

so each leg equals 3x. 3x+3x+x=28.
7x=28
28/7 equals 4
base 4
legs 12

2007-03-08 09:48:08 · answer #1 · answered by savage708 3 · 0 0

ok watch this let base = b , each leg = 3b
perimeter of triangle = b + 2 legs = b + 3b + 3b = 7b
7b = 28 then b = 28 / 7 = 4
then leg = 12 and base = 4

2007-03-08 10:17:11 · answer #2 · answered by emy 3 · 0 0

Let the base be B. Then B + 3B + 3B = 28, so B = 4 and the other two sides are each 12.

2007-03-08 09:44:25 · answer #3 · answered by Anonymous · 1 0

perimeter = base + 2*leg
leg=3*base
perimeter=28
therefore, 28=base+2*(3*Base)
28=base+6base=7base
7base=28m,
base=4m
leg=3*base=3*4=12m
perimeter=base+leg+leg=4+12+12=28

2007-03-08 09:50:30 · answer #4 · answered by David R 1 · 0 0

Doing it in my head , 12, 12, 4.

2007-03-08 09:46:51 · answer #5 · answered by Wonka 5 · 0 0

b = base

b + 3b + 3b = 28
7b = 28
b = 4

base = 4, sides = 3(4) = 12

2007-03-08 09:44:26 · answer #6 · answered by Mathematica 7 · 1 0

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2016-12-05 10:33:56 · answer #7 · answered by ? 4 · 0 0

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