20 = 5 x 4
15 = 5 x 3
35 = 5 x 7
They have 5 in common.
LCM = 5 x 4 x 3 x 7 = 60 x 7 = 420
2007-03-08 09:35:37
·
answer #1
·
answered by ecolink 7
·
0⤊
0⤋
Factor each number, and note which factors are common to all three numbers. In this case:
2 x 2 x 5; 3 x 5, and 7 x 5. Here, the only common factor is 5. Extract that from each of the products, and multiply it by the product of what is left: 5 x (2 x 2) x (3) x (7). The result is the least common multiple, in this case 420.
2007-03-08 17:38:50
·
answer #2
·
answered by Anonymous
·
0⤊
0⤋
Here's an interesting tip for doing LCMs - break each number down into prime numbers.
The primes that go into each number are:
20: 2, 2,, 5
15: 3, 5
35: 5, 7
Now, count the primes
20: 2 (one), 5 (one)
15: 3 (once), 5 (once)
35: 5 (one), and 7 (one)
Now you take each prime number, and multiply it by the maximum number times it was used IN ANY ONE NUMBER.
3, 5, and 7 were each used once. Two was used twice.
Multiply the primes
2*2*3*5*7 = 420
2007-03-08 17:40:58
·
answer #3
·
answered by Brian L 7
·
0⤊
0⤋
well..
break them all down...
20:
2*10 = 2*2*5
15:
3*5
35:
5*7
Now multiply all the factors together... but dont include factors that are common to all the numbers:
lcm = 2*2*3*5*7 = 420
2007-03-08 17:40:21
·
answer #4
·
answered by Michael Dino C 4
·
0⤊
0⤋
20 = 2*2*5
15 = 3*5
35 = 5*7
LCM = 7*5*3*4 = 420
2007-03-08 17:40:03
·
answer #5
·
answered by ironduke8159 7
·
0⤊
0⤋
put each in to multiples of prime numbers
20= 5*2*2
15=5*3
35=5*7
Then use all the primes necessary to make any one number.
i.e. 5*2*2*3*7 = 420
2007-03-08 17:42:09
·
answer #6
·
answered by David R 1
·
0⤊
0⤋
420
2007-03-08 17:38:10
·
answer #7
·
answered by El Viejo Pantera 3
·
0⤊
0⤋
420
2007-03-08 17:35:57
·
answer #8
·
answered by darthfroehlious 2
·
0⤊
0⤋
5 is the least common multiple
2007-03-08 17:37:54
·
answer #9
·
answered by Jonny 5
·
0⤊
1⤋
they are all multiples of 5.
2007-03-08 17:36:01
·
answer #10
·
answered by wendy_da_goodlil_witch 7
·
0⤊
1⤋