How often would a clock which looses 1 second every day be perfectly accurate again?

Question

Please explain for me, this is confusing...

I remember seeing the answer somewhere, but I can't remember. I would just to like to know how it's calculated... I think it was like 400+ years or something, I don't remember...

1st answerer: You're lacking the "explain" part.

Nevermind, you edited... Thanks

Answer 1

118.275.. years for a 12 hour clock

For a 12 hour clock, you will need to lose 12 hours exactly for it to be accurate again.
12 hours = 720 minutes = 43200 seconds.
To lose that will take 43200 days.
43200 days / 365.25 ≈ 118.275 years.

Double that for a 24 hour clock.


NOTE TO northstar:
The year 2100 is not a leap year, therefore 29 leap years and thus 118 years 101 days if started today.

If started this date next year, 118 years 102 days (since we lose the leap day in 2008).
And if it had started this date 1907, 118 years 100 days.
(since 2000 was a leap year)

Answer 2

Assuming you have a twelve hour clock:

The number of seconds in twelve hours is:
12*60*60 = 43,200 seconds

It will take 43,200 days to lose those seconds and become accurate again. That equates to

43,200 days = 118 years, 100 days

This assumes 30 leap years since we are starting with the year 2007.

A 24 hour clock would take twice as long.