Mine is to be a special contributor you have to ask alot of questions. I'm generally an answerer. I've only asked about 100 questions. I do have 20,000 points. Oh! Well.
2007-03-08 08:37:52 · 22 answers · asked by Ron B. 7 in Entertainment & Music ➔ Polls & Surveys
i think they do look at a balance of questions/answers. i ask alot and answer alot... hmmm. wish they would just post something that tells us!! oh, and i'm envious of your points. (:
2007-03-08 08:42:27 · answer #1 · answered by lynn 5 · 1⤊ 2⤋
I think a contributor is someone who gets a lot of best answers in a certain category...
2007-03-08 16:47:29 · answer #2 · answered by *Burning Love* 1 · 1⤊ 0⤋
Wow, you must have a whole lot of time to spend answering questions or you may give one or two word answers to many, many questions.
I would rather have my 'less than 3,000' and give meaningful answers to a few questioners who need help, than just rack up points.
BTW, I have 12% best answers.
2007-03-08 16:43:20 · answer #3 · answered by Nepetarias 6 · 1⤊ 0⤋
I haven't asked that many and I'm in three categories, go figure. There's lots in level 6 with no steenkin bodges.
2007-03-08 16:42:45 · answer #4 · answered by Crash 7 · 0⤊ 0⤋
i asked only 13 questions but i have answered 3000+ q's
2007-03-08 16:43:45 · answer #5 · answered by mara 7 · 0⤊ 0⤋
That's weird...I have about a third of your points. I do ask alot more than I answer.
2007-03-08 16:41:30 · answer #6 · answered by Anonymous · 0⤊ 0⤋
I think it's more the answering and getting points other than just asking and losing points.
2007-03-08 16:41:06 · answer #7 · answered by Èrìç G. (guardians611) 5 · 1⤊ 2⤋
Maybe yahoo logs peoples time spent on this site.
2007-03-08 16:42:25 · answer #8 · answered by ♫That'll be the Day♫ 6 · 0⤊ 0⤋
You dont have to ask a lot of questions you just have to be an yahoo addict
2007-03-08 16:41:04 · answer #9 · answered by yaya t 6 · 6⤊ 0⤋
you have to ask a lot of questions in one category and answered a lot in that category
2007-03-08 16:41:06 · answer #10 · answered by valgal115 6 · 2⤊ 0⤋