x^2=36-y^2
and please help me figure out how to graph it!
2007-03-08 08:25:16 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
It is a circle of radius 6, centred at the origin.
Reason . . . it can be rearranged in the form:
x² + y² = 36. Compare this with x² + y² = r², the standard equation of a circle with radius r, centre the origin, and you will see why.
To draw it, set a pair of compasses to radius 6 units and centre the point at the origin on a set of axes, and draw it. Label +6 and -6 where the circle cuts the x-axis, and +6 and -6 where it cuts the y-axis.
2007-03-08 08:32:31 · answer #1 · answered by sumzrfun 3 · 0⤊ 1⤋
It's a circle of radius 6, with its center at the point (0,0). To verify this, you can rewrite the equation in the form x^2 + y^2 = radius^2. Add y^2 to both sides and rewrite the equation as:
x^2 + y^2 = 36.
And since 36 = 6^2, you know that this equation corresponds to a circle of radius 6.
Graphing it should be pretty simple -- just use a compass to draw a circle of radius 6 units centered around the point (0,0).
2007-03-08 08:39:10 · answer #2 · answered by buggi22 2 · 0⤊ 0⤋
you can rearrange it to x^2 + y^2 =36. Since the numbers in front of x and y are equal (1), it's a circle. You can also write this x^2 + y^2 =6^2. So the circle has a radius of 6. Plug in 0 for x, then do it for y and you can see where it hits the x and y axis. Example y=0, x^2 = 6^2, so when y=0, x =6 and x=-6. I hope this helps.
2007-03-08 08:35:41 · answer #3 · answered by mrplusminus 2 · 0⤊ 0⤋
Rearranging the equation you have
y^2+x^2=36
This is the equation of a circle. The center is (0,0) because in standard from (y-k)^2 + (x-h)^2= (radius)^2
So the k and h values are both zero and the radius is 6. I would try reading the chapter or looking at your notes or even paying attention in class if you're this lost
2007-03-08 08:39:12 · answer #4 · answered by Zajebe 2 · 0⤊ 0⤋
x^2=36-y^2
x^2 + y^2 = 36
This is the equation of a circle with cente at origin (0,0) and radius = sqrt(36) = 6.
So just put a compass at (0,0) , stretch it ou to (6,0) and draw the circle.
2007-03-08 08:34:56 · answer #5 · answered by ironduke8159 7 · 0⤊ 0⤋
The equation is a circle. The middle point is (0,0) and the radius is 6.
2007-03-08 08:34:58 · answer #6 · answered by Twenty20 3 · 0⤊ 0⤋
It's a simple circle with centre the origin (0,0) and a radius of 6 units.
2007-03-08 08:34:15 · answer #7 · answered by VINCENT R 1 · 0⤊ 0⤋
i think its 2 parabolas
2007-03-08 08:33:30 · answer #8 · answered by Anonymous · 0⤊ 2⤋