X ≤0 and x + 6 >3?

1 ⤊

how do i solve

2007-03-08 08:21:28 · 5 answers · asked by kim r 1 in Science & Mathematics ➔ Mathematics

Isolate x in your second equation. x > 3 - 6 = -3, so x > -3

Since x (<=) 0 (that's less than or equal to) and x > -3,
-3 < x <= 0

2007-03-08 08:24:11 · answer #1 · answered by Anonymous · 0⤊ 0⤋

0 => x > -3

2007-03-08 16:23:58 · answer #2 · answered by John S 6 · 0⤊ 1⤋

you subtract 6 from both sides and you are left with x> -3 .
So 0> or = X>-3 or x is between 0 and -3

2007-03-08 16:26:56 · answer #3 · answered by miggyjb 2 · 1⤊ 0⤋

x + 6 > 3 // subtract 6

x > -3

Now, x must be smaller than or equal to zero, so
0 >= x > -3

2007-03-08 16:25:37 · answer #4 · answered by Amit Y 5 · 0⤊ 0⤋

i agree with that

2007-03-08 16:29:00 · answer #5 · answered by Anonymous · 0⤊ 0⤋