2007-03-08 08:11:16 · 7 answers · asked by Tay Tay 1 in Science & Mathematics ➔ Mathematics
x + x + 2 + x + 4 = 36
3x + 6 = 36
3x + 6 - 6 = 36 - 6
3x = 30
3x / 3 = 30 / 3
x = 30 / 3
x = 10
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The numbers are 10, 12, and 14
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2007-03-08 08:23:46 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
Here's a way to do it for any sum.
If x is the smallest of the three even integers, then the next even integer is 2 more, x + 2, and the next one is 2 more than that, x + 4.
So, x + x + 2 + x + 4 = 36. 3x + 6 = 36. Solve for x by subtracting 6 from both sides. 3x = 30. So x = 10.
And then, you have that the numbers are 10,12,and 14.
Also, if the numbers are three consecutive even integers, the sum has to be a multiple of 3.
2007-03-08 16:18:46 · answer #2 · answered by s_h_mc 4 · 0⤊ 0⤋
10 + 12 + 14 = 36
2007-03-08 16:19:38 · answer #3 · answered by Al Gene Ang 2 · 0⤊ 0⤋
10 + 12 + 14 = 36
2007-03-08 16:15:45 · answer #4 · answered by PH 2 · 1⤊ 0⤋
Three consecutive even integers can be expressed as x. x+2, and x+4. Therefore:
x + (x+2) + (x+4) = 36
Combine like terms, and solve for x
2007-03-08 16:15:52 · answer #5 · answered by dogsafire 7 · 1⤊ 0⤋
36/3 = 12, so the middle number is 12. 12-2 = 10... 12+2 =14... so the numbers are 10,12,14.
2007-03-08 16:19:22 · answer #6 · answered by theoryofgame 7 · 0⤊ 0⤋
Pick a set, try it, and adjust.
10+12+14=36
There, I got it in one try.
2007-03-08 16:15:36 · answer #7 · answered by wayfaroutthere 7 · 1⤊ 0⤋