A surveyor standing 55 meters from the base of a building measures the angle to the top of the building and finds it to be 37 degrees. The surveyor then measures the angle to the top of the radio tower on the building and finds that it is 50 degrees. How tall is the radio tower?
2007-03-08 08:00:58 · 6 answers · asked by Rachel 2 in Science & Mathematics ➔ Mathematics
55 tan(50deg)- 55 tan(37deg)
2007-03-08 08:10:17 · answer #1 · answered by diamond 3 · 0⤊ 0⤋
Use trig...
use the tan function...tan is opposite side over adjacent. so basically, inverse tan of the angle = x/side
do that for both the building angle
and then the radio tower angle
subtract the x value for the building from the x value of the radio tower and you will get your solution
2007-03-08 08:07:38 · answer #2 · answered by Mantis 2 · 0⤊ 0⤋
enable x be the tens digit and y be those digit. 10x + y = 7(x+y)=7x + 7y 10x + y - 18 = 10y + x rearrange 3x=6y 9x -18=9y Multiply 1st equation by using 3 9x=18y then subtract 0x +18 = 9y y=2 3x=6(2) = 12 x=4 so the extensive kind is 40 two verify 40 two=7(4+2) specific 40 two-18 = 24 specific
2016-12-18 08:42:56 · answer #3 · answered by ? 4 · 0⤊ 0⤋
Denote by x the hight of the building and by y the hight of the radio tower.
There are two equalities one uses to find y.
tan 37 =x/55 which helps to find x
tan 50 = (x+y)/55 which helps to find x+y.
As one already knows x from above one can find y.
2007-03-08 08:16:00 · answer #4 · answered by E 1 · 0⤊ 1⤋
you would have to know how tall the building is before you could calculate how tall the tower is. based on the formula you gave anyway
2007-03-08 08:10:23 · answer #5 · answered by BOB H 4 · 0⤊ 0⤋
h = 55 tan(50)/[tan(50)-tan(37)] = 149.58 m
2007-03-08 08:11:57 · answer #6 · answered by sahsjing 7 · 0⤊ 0⤋