I need help with this problem.... If possible, can you show the work so I can learn?
sinx secx = tanx
2007-03-08 07:53:41 · 6 answers · asked by Nick36 1 in Science & Mathematics ➔ Mathematics
Remember that secx = 1/cosx
sinx * (1/cosx) = sinx/cosx
And we know that tanx = sinx/cosx, by definition.
2007-03-08 07:58:09 · answer #1 · answered by Anonymous · 0⤊ 1⤋
sinxsecx
= sinx(1/cosx)
=sinx/cosx
by definition,
tanx = sinx/conx.
Simple. Okay na ba?
Pls. read Philippians 4:6
2007-03-08 15:58:24 · answer #2 · answered by johnoodles 2 · 0⤊ 1⤋
The secret to doing this type of problem is to remember the relationship of the functions to the parts of a right triangle
sin = opposite/hypotenuse
secant = hypotenuse/adjacent
tan = opposite/adjacent
since the you have sin*sec that is the same as saying opposite/hypotenuse * hypotenuse/adjacent
You can see that the hypotenuse divides out, leaving you with opposite/adjacent which is tan
2007-03-08 16:01:23 · answer #3 · answered by dogsafire 7 · 0⤊ 1⤋
sin x = opposite leg / hypotenuse
sec x = 1 / cos x = 1/(adjacent leg/hypotenuse) = hypotenuse/adjacent leg
therefore sinx * secx = (o/h)(h/a)= o/a
opposite leg/adjecent leg = tan x
Hope this helps!
2007-03-08 15:59:25 · answer #4 · answered by Anonymous · 0⤊ 1⤋
sinxsecx = tanx
sinx(1/cosx)
=tanx.
secx is equal to 1divided by cosx. so we replace sex by 1/cosx. we are then left with sinx/cosx which is equal to tanx.
and the problem is solved.
2007-03-08 16:31:49 · answer #5 · answered by Twenty20 3 · 0⤊ 0⤋
sec = 1/cos so left = sin/cos and right = sin/cos (identity)
2007-03-08 16:01:22 · answer #6 · answered by Starber 1 · 0⤊ 1⤋