22 mg of a certain protein was dissolved in water to make a solution of 3.50 mL at 27C?

Question

22 mg of a certain protein was dissolved in water to make a solution of 3.50 mL at 27C. If the osmotic pressure is 1.35 torr, what is the molecular mass of the protein?



To enter an answer in scientific notation use an e

6.022 x 1023 = 6.022e23

1.340 x 10-8 = 1.340e-8

Enter a numeric answer only, do not enter units.

Answer 1

Please see my answer to a similar qusetion:

http://answers.yahoo.com/question/index;_ylt=AuI.Nm94DclkMFghz2XYKWcExgt.?qid=20070308111112AAz1zq0

Use the same principle, just plug your numbers in. Which by the way are almost exactly the same as your problem.

Answer 2

I guess you can use my question as a ref.


22 mg of a certain protein was dissolved in water to make a solution of 4.50 mL at 26C. If the osmotic pressure is 1.25 torr, what is the molecular mass of the protein?

To enter an answer in scientific notation use an e




6.022 x 1023 = 6.022e23



1.340 x 10-8 = 1.340e-8


Enter a numeric answer only, do not enter units.

Correct, computer gets: 72931.7185422222

This is how I solved it:

(0.022)*(0.082)*(273+26)/((1.25/760)*0.0045)=72931.7185422222