Disulfur dichloride, S2Cl2, can be made by treating molten sulfur with chlorine gas, according to the following unbalanced equation:
S8(l) + Cl2(g) ® S2Cl2(g)
How much S2Cl2 (in grams) can be produced if you start with 38.10 grams of sulfur, and 84.87 grams of chlorine gas?
2007-03-08 07:32:18 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
The problem is a "limiting reactant" problem, but you must first, balance the equation.
Convert mass of sulfur to moles of S8 using molar mass of S8. Use coefficients of balanced equation to convert moles of S8 to moles of S2Cl2. Then, determine mass of that many moles of S2Cl2 using molar mass of S2Cl2.
Next, repeat the entire process beginning with the mass of chlorine, converting that to moles of Cl2. With balanced equation, calculate moles of S2Cl2 and finally mass of S2Cl2.
Your final answer will be the SMALLER of the two masses calculated above. That initial reactant is the limiting reactant.
2007-03-08 07:40:11 · answer #1 · answered by hcbiochem 7 · 0⤊ 0⤋
Hmm i think it's impossible
2007-03-08 07:45:09 · answer #2 · answered by Anonymous · 0⤊ 0⤋