Solving quadratic eauations by the quadratic formula?

Question

Okay u anyone out of school probably wont understand this becauze it is hard! And very weird! But it is about the quadratic formula! The formula is -b +/- the square root of b to the 2 - 4ac divide by 2a! Well this problem is -6x to the second-3x+2 and i did the formula and everything and came up with 3+/- the square root of 57 divided by 12! did i do something wrong? If u have the same book as me, well i live in Indiana and my book is "Algebra 1" by McDougal little and it has a earth on it with 3 kids doing different thing and it is marron with a navy line half way through it and it is on pg 536 number 40, or u can go to ww.classzone.com

Answer 1

There's nothing wrong with it. You answered the question correctly (except the answer is divided by -12).

This is how it is solved:
y = - 6x² - 3x + 2, using -b±√(b² - 4ac) / 2a

a = -6, b = -3, c = 2

= -(-3)±√(-3)² - 4(-6)(2)/ 2(-6)
= 3±√(9+48) / -12
= (3±√57)/ -12

= (3+√57)/ -12 and (3-√57)/ -12
^^ This is the answer

For this answer, you can't simplify it anymore, because the √57 doesn't have a number that is multiplied by a squared number.
Like
√8
= √(4·2)
= √4·√2
= 2√2

The number 57 doesn't have a square number, so it can't be reduced anymore, even if the number 3 and 12 can be reduced. If you do reduce 3 and 12 without √57, your answer would completely change!

Don't worry, you did it right! =)

Answer 2

question variety a million : For this equation x^2 - 7*x - a million = - 7 , answer right here questions : A. discover the roots utilising Quadratic formula ! B. Use factorization to discover the inspiration of the equation ! C. Use ending up the sq. to discover the inspiration of the equation ! answer variety a million : First, we could coach equation : x^2 - 7*x - a million = - 7 , right into a*x^2+b*x+c=0 type. x^2 - 7*x - a million = - 7 , pass each little thing interior the the main suitable option hand area, to the left hand area of the equation <=> x^2 - 7*x - a million - ( - 7 ) = 0 , that's a similar with <=> x^2 - 7*x - a million + ( 7 ) =0 , now open the bracket and we get <=> x^2 - 7*x + 6 = 0 The equation x^2 - 7*x + 6 = 0 is already in a*x^2+b*x+c=0 type. In that type, we are able to particularly derive that the fee of a = a million, b = -7, c = 6. 1A. discover the roots utilising Quadratic formula ! Use the formula, x1 = (-b+sqrt(b^2-4*a*c))/(2*a) and x2 = (-b-sqrt(b^2-4*a*c))/(2*a) We had be attentive to that a = a million, b = -7 and c = 6, we could subtitute a,b,c interior the abc formula, with thos values. Which produce x1 = (-(-7) + sqrt( (-7)^2 - 4 * (a million)*(6)))/(2*a million) and x2 = (-(-7) - sqrt( (-7)^2 - 4 * (a million)*(6)))/(2*a million) that's a similar with x1 = ( 7 + sqrt( 40 9-24))/(2) and x2 = ( 7 - sqrt( 40 9-24))/(2) Which make x1 = ( 7 + sqrt( 25))/(2) and x2 = ( 7 - sqrt( 25))/(2) So we get x1 = ( 7 + 5 )/(2) and x2 = ( 7 - 5 )/(2) So we've the solutions x1 = 6 and x2 = a million 1B. Use factorization to discover the inspiration of the equation ! x^2 - 7*x + 6 = 0 ( x - 6 ) * ( x - a million ) = 0 The solutions are x1 = 6 and x2 = a million 1C. Use ending up the sq. to discover the inspiration of the equation ! x^2 - 7*x + 6 = 0 ,divide the two area with a million Then we get x^2 - 7*x + 6 = 0 , all of us be attentive to that the coefficient of x is -7 we could use the certainty that ( x + q )^2 = x^2 + 2*q*x + q^2 , and assume that q = -7/2 = -3.5 So we've make the equation into x^2 - 7*x + 12.25 - 6.25 = 0 which could be became into ( x - 3.5 )^2 - 6.25 = 0 So we are able to get (( x - 3.5 ) - 2.5 ) * (( x - 3.5 ) + 2.5 ) = 0 by skill of utilising the associative regulation we get ( x - 3.5 - 2.5 ) * ( x - 3.5 + 2.5 ) = 0 And it particularly is an identical with ( x - 6 ) * ( x - a million ) = 0 So we've been given the solutions as x1 = 6 and x2 = a million

Answer 3

I get the same answer. Just be careful that you have the (3 +/- sqrt of 57) all over 12. Not just the sqrt of 57 over the 12.

Some teachers want that answer reduced. If so, you get
3/12 +/-(sqrt 57)/12 or
1/4 +/- (sqrt57)/12

Answer 4

okay so you know that
-6x ^2 is A
-3x is B
2 is C

Now you plug in -(-6) Square root of 9- 4 (-6)(2) /12



6 +/- square root 9+48 / 12

which is the same as what you got.

Answer 5

fyi - i'm way out of school and i not only understand the quadratic formula, but i work with it probably more than you do. AND it is easy. so stop leaping to judgement about people or you will have much difficulty in this world.

also, you might consider giving us the entire problem to work on.

Answer 6

Interesting story----do you have a question?