algebra II?

Question

i need help with three problems
ln(x)=ln(3xs-12)
log(x-2)=log(x-8)=log7
f(x)=x^2+3 and g(x)=x+1 find g(f(x))

Answer 1

if the logs of two expressions are equal then the expressions are equal.

ln(x) =ln(3xs-12)
x = 3xs -12
x+12 = 3xs
s = (x+12)/3x
if the s is a typo error then the equation is

x+12 = 3x
2x = 12
x =6


something is wrong with the second problem
log(x-2) = log 7 and log(x-8) =log 7
this means that x-2 =7 and x-8 =7 which is an obvious impossibility.

f(x) = x^2+3 g(x) = x+1

g(f(x)) = x^2 +3 +1 = x^2 + 4

Answer 2

For the second equation i.e log(x-2)=log(x-8)=log7
make two equations
log(x-2)=log7
log(x-8)=log7
then solve simultaneously.
i think you get x=o.
for hte last equation
g(f(x))=x^2+4.

Answer 3

I think the last one is solved like this but i am not completely sure:

g(fx)= (x^2 +3) +1
g(fx)=x^2+4

Answer 4

You can burn natural logs in your fireplace you know?

Answer 5

!Your right,you need help!