factor the trinomial?

0 ⤊

b^2-4b-32

2007-03-08 03:37:44 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

b^2-8b+4b-32
=(b-8)(b+4)

2007-03-08 03:44:44 · answer #1 · answered by Maths Rocks 4 · 0⤊ 0⤋

Ans:
b^2-4b-32=(b-8)(b+4)
Explanation:
Take the factors of -32 such a way that their sum =-4
and product = -32

2007-03-08 11:45:11 · answer #2 · answered by ckoottunkal 2 · 0⤊ 0⤋

b^2-4b-32=0
b^2-8b+4b-32=0
b(b-8) +4(b-8)
(b+4) (b-8)
b=-4 b=8

2007-03-08 11:47:02 · answer #3 · answered by omo 2 · 0⤊ 0⤋

b^2 -4b -32

b^2 - 8b + 4b -32

b(b - 8) + 4(b -8)

(b+4)(b-8)

2007-03-08 11:46:16 · answer #4 · answered by Tom C 1 · 0⤊ 0⤋

( b - 8)(b + 4)

2007-03-08 11:40:18 · answer #5 · answered by Marissa 2 · 0⤊ 0⤋