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factor out all common monimals first
35x^3-61x^2+8x

2007-03-08 03:37:06 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

35x^3-61x^2+8x
=x(35x^2-61x+8)
=x(35x^2-56x-5x+8)
=x{7x(5x-8)-1(5x-8)}
=x(5x-8)(7x-1)

2007-03-08 03:50:56 · answer #1 · answered by alpha 7 · 0 0

Ans:
35x^3-61x^2+8x=x(35^x-61x+8)
=x[(7x-1)(5x-8)]
Hence the factors are x,(7x-1) and (5x-8)

2007-03-08 11:54:57 · answer #2 · answered by ckoottunkal 2 · 0 0

x(35x^2 - 61x + 8)
x(7x - 1)(5x - 8).

2007-03-08 11:43:39 · answer #3 · answered by Newbody 4 · 0 0

x(35x^2-61x+8)
=x(35x^2-56x-5x+8)
=x(7x(5x-8)-1(5x-8))
=x(7x-1)(5x-8)

2007-03-08 11:54:38 · answer #4 · answered by Maths Rocks 4 · 0 0

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