math help....?

Question

1. Find the range of the function: M(x) = x2 + 5x + 2.
D= {-1,-2,-4}

A.{4,-2}
B.{-4,2}
C.{-4,-2}
D.{4,2}

Answer 1

M(-1)=1-5+2=-2
M(-4)=16-20+2=-2
M(-2)=4-10+2=-4
Ans:{-4,-2}

Answer 2

D={-1,-2,-4} is know as the domain(x-values) of the function.
So if you want to find the range(y-values) of a function you substitute the x-values in the equation one-by-one and the resulting number will be your range. when you substitute (-1) or (-4) in the equation you get -2 and when you substitute( -2) in the equation you get (- 4).

So the answer is C{-4,-2}

Answer 3

Ans: C
Explanation:
M(-1)=(-1)^2+5(-1)+2=-2
M(-2)=(-2)^2+5(-2)+2 =-4
M(-4)=(-4)^2+5(-4)+2 =-2
M(x)={(-1,-2),(-2,-4),(-4,-2)}
Range of M(X) =the set of y-values
={-4,-2}

Answer 4

That means you have to find the least possible output (answer) and the most possible output as you boundries. That is, as the two other people said {-4 (least), - 2(most)}. The other 2 is also in the range but is not a boundry since it is in between the other two.

Answer 5

M(-1) = -2
M(-2) = -4
M(-4) = -2
Answer is C.