2007-03-08 02:43:45 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Split it into 5 rectangles.
Bottom piece is one rectangle; top piece is another.
Left & Right arms are two equal rectangles.
The piece in the middle is the 5th rectangle, having the same height as the "arms", and same width as the top & bottom pieces.
2007-03-08 03:02:08 · answer #1 · answered by Anonymous · 0⤊ 0⤋
if you know the length of the sides you should break the shape down into sections, find the area of each section & then ad them together. so for a cross you would find the area for the middle & each of the points seperately & then add them up.
2007-03-08 10:48:19 · answer #2 · answered by Just me 5 · 0⤊ 0⤋
This is really quite easily solved. The total area of the cross would be the sum of the areas of the individual arms minus the area of their intersection.
Let w be the width of one arm. Let l be its length. Then its area is (l w).
Let w' be the width of the second arm. Let its length be l'. Then its area is (l' w').
The total area of the cross can be found by this equation:
A = (l w) + (l' w') - w w'.
2007-03-08 11:09:15 · answer #3 · answered by MathBioMajor 7 · 1⤊ 0⤋
divide it into parts. the first part would be the part on top of the horizontal line,the second would be the horizontal bar and then the last one would be the part below the horizontal. add them all up and you got ur answer.
2007-03-08 10:48:53 · answer #4 · answered by thesavageworm 3 · 0⤊ 0⤋