Stoichiometry reaction: C3H8 + 5 02--------> 3 CO2 + 4 H20?

Question

a) what is the mass of H20 produced from the reaction of 6.3g of propane?

b)how many molecules of H2O are produced when 2 moles of O2 are reacted with axcess of propane?

c)how many atoms of hydrogen in water are produced when 2.4 moles of propane are reacted?

d)how many molecules of CO2 are produced when 2.3 x 10^6 atoms of O2 are reacted?

e)what is mass of CO2 produced when 6.5g of propane is reacted with 14.2g of O2?

Answer 1

a) MM propane =44 g/mole
6.3/44= 0.143 mole
1 mole propane : 4 moles H2O = 0.143 : x
x=0.573 mole H2O
0.573(18)=10.3 g

b) 5 moles O2 : 4 moles H2O = 2 : x
x=1.6 moles H2O>>9.63 10^23 molecules H2O

c) 1mole propane : 4 moles H2O=2.4 : x
x=9.6 moles H2O=19.2 moles H>>1.15 10^25 atoms

d)We can't speak of atoms of O2.

e)6.5/44=0.148 mole propane
14.2/32=0.444 mole O2 limiting reactant
5moles O2 : 3 moles CO2 = 0.444 : x
x=0.266 mole CO2 MM=44 >>11.7 g