2007-03-07 23:56:34 · 5 answers · asked by jardale 1 in Science & Mathematics ➔ Mathematics
8/3x-3=2/3x+15
8x=2x+54
6x=54
x=9
substitute..
8/3(9)-3=2/3(9)+15
24-3=6+15
21=21
2007-03-08 00:05:43 · answer #1 · answered by Anonymous · 0⤊ 0⤋
a million) 15m+3=-12 15m=-15 m=-a million 2)3/2 x= 3 3x=6 x=2 3)-7x= -15/2 - 6/2 -7x=-21/2 -14x= -21 14x = 21 x = 3/2 4) 4x + 6x + a million=3 10x+a million = 3 10x = 2 x= a million/5 5) 3/2 x + 12 =6x 12= 9/2 x 24 = 9x x= 24/9 x= 8/3
2016-12-14 13:47:19 · answer #2 · answered by ? 4 · 0⤊ 0⤋
8/3x -3= 2/3x +15
subtract the 2/3x from both sides
6/3x -3 = 15
add 3 to both sides
6/3x = 18
6/3x reduces to 2x
2x=18
divide both sides by 2
x=9
To check plug 9 in wherever there is an x in your original equation.
8/3(9) -3 = 2/3(9) +15
72/3 -3 =18/3 +15
72/3 reduces to 24 and 18/3 reduces to 6
24-3=6+15
21=21 It checks out OK
Hope this helps. I tried to break it down into all of the steps as possible.
2007-03-08 00:05:46 · answer #3 · answered by Anonymous · 1⤊ 0⤋
Multiply equation by 3:
8x - 9 = 2x + 45
Add 9-2x to both sides:
6x = 54
Divide by 6:
x=9
2007-03-08 00:06:21 · answer #4 · answered by blighmaster 3 · 0⤊ 0⤋
first of all u dont get RHS =LHS.
then how do v solve
i get it like this ............. -8=10
2007-03-08 00:05:27 · answer #5 · answered by Anonymous · 0⤊ 0⤋