(x-a)(x-b)(x-c)(x-d)..........(x-y)(x-z) = ?
2007-03-07 20:06:03 · 18 answers · asked by vrpraman 1 in Science & Mathematics ➔ Mathematics
Answer is zero
(x-a)(x-b)...(x-x)(x-y)(x-z)=0
x-a)(x-b)...(0)(x-y)(x-z)=0
0=0
:-))
2007-03-07 21:23:38 · answer #1 · answered by cool_boy 1 · 0⤊ 0⤋
If the given `x` is same as that of the `x` of the alphabetical order the answer is 0 because a stage will come when we will have (x-x). So, the product of the whole series will become 0 as one of the term will be 0.
But if the given `x` is different from the alphabetical order, then i will die calculating the question but i may not be able to solve it.
2007-03-08 10:35:24 · answer #2 · answered by shailendra s 3 · 0⤊ 0⤋
If the series continues, you will eventually have (x - x) which equals 0. As it is multiplication you have a number multiplied by 0, which always equals 0
2007-03-08 04:13:08 · answer #3 · answered by Tom :: Athier than Thou 6 · 0⤊ 0⤋
well,
we dont know what (x-a) is but when you get to (x-x) the result is 0 so that the answer is 0
2007-03-08 05:27:11 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Wow !!! Everyone is saying it is zero. As I am from a democratic country I will go with the majority.
Did I told the answer. I guess I did :)
2007-03-08 04:29:15 · answer #5 · answered by HaK 1 · 0⤊ 2⤋
Answer is "zero" because the term (x-x) gives zero.
2007-03-09 02:58:45 · answer #6 · answered by Get to Know 2 · 0⤊ 0⤋
0 since the term (x-x) is equal to zero and any number multiplied to zero is equal to zero
2007-03-08 04:32:41 · answer #7 · answered by jsb 2 · 0⤊ 0⤋
x^4 + x^3 + x^2 + x - x(a+b+c+d) + a( b+c+d) + b(c+d) + cd...
ha ha....
actually... answer is Zero... 0...
:-)
2007-03-08 04:16:12 · answer #8 · answered by Ally 3 · 0⤊ 1⤋
(x-x)=0
2007-03-08 04:14:30 · answer #9 · answered by sultan 4 · 0⤊ 0⤋
a sweet big zero
2007-03-08 05:05:20 · answer #10 · answered by mou 2 · 0⤊ 0⤋