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A hot piece of metal splaced in an equal mass of water. Which will have the greater temperature change, the metal or H2O? and why?

2007-03-07 19:17:44 · 6 answers · asked by totally_confused 1 in Science & Mathematics Physics

6 answers

The metal would, because water has a far greater specific heat capacity than metals. It takes more energy to raise the temperate of water than the same mass of metal. Eventually, both the metal and water will reach the same temperature, but this final temperature wil be a lot closer to the original temperature of water than the original temperature of the metal.

Read the wiki article if you need to be sure about this.

2007-03-07 19:53:26 · answer #1 · answered by Scythian1950 7 · 0 0

The metal will have a greater temperature change, because it is the lower specific heat capacity.

After a longer time water and the metal piece will approach the same temperature.The heat transferred during this process between metal M and water W equals the change of energy of both metal and water. It is given by:
ΔQ = mW·cW·(TW₁ - TW₂) =+mW·cW·ΔTW
ΔQ = mM·cM·(TM₁ - TM₂) = mM·cM·ΔTM
(where m-mass , c-specific heat capacity T-temperature)

The masses are the same. Therefore the absolute value of the Temperature changes are related by
|ΔTW| / |ΔTM| = cpM/cpW

Liquid water has a relatively high specific heat capacity of
cW = 4.18 J·K⁻¹·g⁻¹
Metals usually have a specific heat capacity of
cM ≈ 0.1 .... 1 J·K⁻¹·g⁻¹.
That means, depending on the kind of metal its temperature change will be about 4 - 40 times higher than the temperature change of water.

Because of the 1st law of thermodynamics (=conservation of energy) holds at any time, this relation hold for the dynamic change of the temperature in terms of average temperatures.
There is only a difference in the deviation from average temperature. Metals have a high heat conductivity. Therefore the temperature differences in the metal piece will be very small. In contrast water has a low heat conductivity. The temperature of water near the metal surface will be significantly above the average. For long term operation these temperature gradients vanish.



Note:
Some alkali metals and alkali earth metals have a specific heat capacity greater than 1 J·K⁻¹·g⁻¹ (but smaller 4.18).
However if you place one of the these metals in water an intensive chemical reaction will occur.

2007-03-07 20:16:36 · answer #2 · answered by schmiso 7 · 0 0

In the short run the water should heat up more than the metal will cool because the metal is denser and will retain heat better than water will retain cold. Also, if the metal is hot enough it will cause some of the water to evaporate there by reducing the volume or mass of the water.

At least that's my best guess as someone who isn't a scientist and hasn't been in a science class in over 10 years.

2007-03-07 19:23:26 · answer #3 · answered by Justin H 7 · 0 0

the water would heat up as fast as the metal lost heat. it is the metals heat loss that is the energy for the waters heat. though the metal could easily stay a solid while white hot (high energy visual radiation), yet the water would change state. so the end result would be less mass of water than the metal once they were cool. i guess.

2007-03-07 19:49:06 · answer #4 · answered by SAINT G 5 · 0 0

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2016-11-23 14:52:13 · answer #5 · answered by ? 4 · 0 0

Due to thermodynamics their temps should equal out over time.

2007-03-07 19:26:42 · answer #6 · answered by psilocyphener 3 · 0 0

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