If the osmotic pressure is 1.35 torr, what is the molecular mass of the protein?

Question

14 mg of a certain protein was dissolved in water to make a solution of 2.50 mL at 26C. If the osmotic pressure is 1.35 torr, what is the molecular mass of the protein?

To enter an answer in scientific notation use an e




6.022 x 1023 = 6.022e23



1.340 x 10-8 = 1.340e-8

Any help would be greatly appreciated!!!!!!!

Answer 1

mole =mass/MW
So C=mole/V = mass/(MW*V)

For osmotic pressure π =CRT so

π =massRT / (MW*V) =>
MW =massRT/ (π *V)
You need to express everything in the appropriate unit
π in atm (760 torr =1 atm)
T in Kelvin
V in L
mass in g
so

MW= 0.014*0.082*(273+26) / ((1.35/760)*0.0025) =77295

Answer 2

You need a book with that info..