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current of unknown magnitude is sent though both wires. The wires are 26.5 cm long and have a center-to-center separation of 0.0525 cm.

Find the current...

2007-03-07 15:49:26 · 1 answers · asked by Anonymous in Science & Mathematics Physics

1 answers

the force exerted on the two wires is

F=uI^2/(2πd) use MKS

2E-5*9.8=4πE-7*I^2*26.5E-2/(2π*0.0525E-2)
I^2=(2E-5*9.8)*(2π*0.0525E-2)/(4πE-7*26.5E-2)=1.94 A^2

I=1.39 A

2007-03-10 08:12:26 · answer #1 · answered by Rob M 4 · 0 0

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