How strong is the electric field that will suspend an oil drop that carries two extra electrons and weighs 6.9x10^-15N?
I know you have to use the formula E = F/q
where E is the electric field and F is the weight. How do you get the q?
2007-03-07 15:07:29 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics
Well, the problem talks about two electrons.
So you get the "q" from those extra electrons :
charge of the electron : 1.6*10^-19 C
2q = 3.2*10^-19 C
E = F / q
F = 6.9*10^-15 = E.3.2*10^-19
E = 2.15*10^4 (N / C)
That's the answer
2007-03-07 15:11:19 · answer #1 · answered by anakin_louix 6 · 0⤊ 0⤋
I think you use the charge on an electron which I believe is 1.6x10^-19 Coulombs. Maybe you double the charge since there are 2 electrons?
F is the force, not the weight, which is why it's given in Newtons :) .
2007-03-07 23:12:42 · answer #2 · answered by sprintdawg007 3 · 0⤊ 0⤋