If 13.30 grams of RbCl are dissolved in water to make a solution of 0.224 L, the density is found to be 1.044?

Question

If 13.30 grams of RbCl are dissolved in water to make a solution of 0.224 L, the density is found to be 1.044 g/cm3. Calculate the molarity of the solute.

Answer 1

The molarity of a solution is the number of moles of solute divided by the number of Liters of solution.

You have the number of grams of RbCl, so

13.30 g / 120.9 g/mol = 0.1100 moles of RbCl

If this makes a solution of 0.224 L, them the Molarity is

0.1100 moles / 0.224 L = 0.491 M

The density is not needed.