How many grams of table salt would have to be dissolved in 115.0 grams of water to lower the freezing point by

Question

1.70 degrees celsius? Kf= 1.86 K-kg/mol for water.

Answer 1

I'll set it up, you can crunch the numbers.
Step 1. Find the mole/kg that lowers the freeze pt by 1.7 C. = 1.7/1.86 (about 0.9)
Step 2. Find the grams in a mole of salt corresponding to the above moles
(about 0.9 x 57 or about 50)
Step 3. Scale this down from 1 kg to 115 g.
( about 50 x 115/1000) = about 5.5 g

Answer 2

that's wrong