chemistry help please?

Question

12 mg of a certain protein was dissolved in water to make a solution of 1.00 mL at 20C. If the osmotic pressure is 1.20 torr, what is the molecular mass of the protein?

Answer 1

The P (Osmotic Pressure in atmospheres) = M (the Molarity) * R (the Gas constant) * T (Kelvin temperature)

or

M = P / RT = 1.20 torr/(760 torr/atm) / (0.0821 L-atm/°K-mol) * (273 + 20) °K = 0.001579 atm / 24.06 L-atm/mol
= 0.00006563 mole/L

12 mg/1.00 mL = 12 grams/ 1.00 L

12 grams = 0.00006563 moles

1.00 moles = 12 grams / 0.00006563

Can you take it from here?